(x+2)*(x-3)=x^2+9

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Solution for (x+2)*(x-3)=x^2+9 equation: 



(x+2)(x-3)=x^2+9

We move all terms to the left:

(x+2)(x-3)-(x^2+9)=0

We get rid of parentheses

-x^2+(x+2)(x-3)-9=0

We multiply parentheses ..

-x^2+(+x^2-3x+2x-6)-9=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-3x+2x-6)-9=0

We get rid of parentheses

-1x^2+x^2-3x+2x-6-9=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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